document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294934>Question 294934</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the surface area of a cylinder </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212696 by </B><A HREF=/tutors/aboutme.mpl?userid=PRMath><B>PRMath(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=PRMath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Think of a cylinder like a can of pop, k?  \r<BR>\n" );
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document.write( "At the top of the can, there is a circle.  At the bottom of the can, there is a circle.  Now if you cut off the top and you cut off the bottom and sort of spread out the can (uncurled it), you'd have a rectangle.\r<BR>\n" );
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document.write( "Now picture this:   \r<BR>\n" );
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document.write( "The height of the rectangle is the height of the can.  Can you picture that?<BR>\n" );
document.write( "The top of the rectangle is REALLY the the circumference of the circle.  How so?  Think about it -- it was a circle until you uncurled it.  So the measure of the circumference of the can will not change simply because you uncurled it, right?\r<BR>\n" );
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document.write( "Sooooo to get the total surface area of the cylinder, you use this equation:\r<BR>\n" );
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document.write( "FIRST find the \"lateral area\" (the rectangle) which is:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28pi%29r+h ALIGN=MIDDLE  ALT=\"2%28pi%29r+h\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "r is the radius<BR>\n" );
document.write( "h is the height\r<BR>\n" );
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document.write( "NEXT find the areas of two bases (the top and bottom of the can).  The area formula for ONE circle is:  Area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%29r%5E2. ALIGN=MIDDLE  ALT=\"%28pi%29r%5E2.\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "r is the radius.\r<BR>\n" );
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document.write( "HOWEVER -- there are TWO circles (the TOP and the BOTTOM of the can) soooo, we have to find the TWO bases so our formula for the TWO bases is:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"2%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "IF we add the lateral area plus the base areas, we'll know the total surface area.  \r<BR>\n" );
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document.write( "Our final equation is:\r<BR>\n" );
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document.write( "Total Area of a Cylinder = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28pi%29rh ALIGN=MIDDLE  ALT=\"2%28pi%29rh\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"2%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Just put in the correct numbers for the radius and height and do the math and voila - you'll have the total surface area.  \r<BR>\n" );
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document.write( "If you need more help, just get a specific question (such as the measurements of a sample problem) and post it here.  I'm sure someone can give you more info if you need it.\r<BR>\n" );
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document.write( "I hope this helps. :-) </SPAN>\n" );
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