document.write( "Question 294997: x^2-y^2=3
\n" ); document.write( "2x+y=3
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Algebra.Com's Answer #212692 by Alan3354(69443)\"\" \"About 
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x^2-y^2=3
\n" ); document.write( "2x+y=3 --> y = -2x + 3
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\n" ); document.write( "Sub for y into the 1st eqn:
\n" ); document.write( "\"x%5E2+-+%28-2x%2B3%29%5E2+=+3\"
\n" ); document.write( "\"-3x%5E2+%2B+12x+-+9+=+3\"
\n" ); document.write( "\"3x%5E2+-+12x+%2B+12+=+0\"
\n" ); document.write( "\"x%5E2+-+4x+%2B+4+=+0\"
\n" ); document.write( "\"%28x-2%29%5E2+=+0\"
\n" ); document.write( "---------------------
\n" ); document.write( "x = 2, y = -1\r
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