document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294998>Question 294998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write a quadratic equation whose solutions are: 1/2 and 10/3 I can get that the first is 6x^2+   +10=0 I cannot figure the middle solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212680 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the solutions are a and b the the equation is (x-a)*(x-b)=0<BR>\n" );
document.write( "a=1/2 and b=10/3<BR>\n" );
document.write( "(x-1/2)*(x-10/3)=0<BR>\n" );
document.write( "Use FOIL to multiply it out.<BR>\n" );
document.write( "F x^2<BR>\n" );
document.write( "O -10x/3<BR>\n" );
document.write( "I -x/2<BR>\n" );
document.write( "L -1/2*-10/3=10/6<BR>\n" );
document.write( "add them all together<BR>\n" );
document.write( "x^2-10x/3-x/2+10/6=0<BR>\n" );
document.write( "We could multiply by 6<BR>\n" );
document.write( "6x^2-20x-3x+10=0<BR>\n" );
document.write( "6x^2-23x+10=0<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );