document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294926>Question 294926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. The measure of the smaller angle is 17 degrees more than one-third the measure of the larger one. Find the measure of the larger angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212678 by </B><A HREF=/tutors/aboutme.mpl?userid=ozybloke><B>ozybloke(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ozybloke><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ozybloke><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplementary angles add up to 180 degrees<BR>\n" );
document.write( "Let x = the measure of the larger angle<BR>\n" );
document.write( "Smaller angle = x/3 + 17<BR>\n" );
document.write( "Therefore:<BR>\n" );
document.write( "x + (x/3 + 17) = 180<BR>\n" );
document.write( "x + x/3 = 180 - 17<BR>\n" );
document.write( "x + x/3 = 163<BR>\n" );
document.write( "Get a common denominator<BR>\n" );
document.write( "3x/3 + x/3 = 163<BR>\n" );
document.write( "Now we can remove the denominator from the equation<BR>\n" );
document.write( "4x/3 = 163<BR>\n" );
document.write( "4x = 489<BR>\n" );
document.write( "Divide both sides by 4<BR>\n" );
document.write( "x = 122.25<sup>0</sup> \r<BR>\n" );
document.write( "\n" );
document.write( "Smaller angle = 180 - 122.5 = 57.5<sup>0</sup> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );