document.write( "Question 294980: Find two consecutive even integers such that the sum of the first and the reciprocal of the second is 9/4.
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\n" ); document.write( "This problem we are to come up with the formula and write it out as if we were teaching someone how to do it. \r
\n" ); document.write( "\n" ); document.write( "So far I think it should look like this (but not really sure):
\n" ); document.write( "1/x+1/x+1=9/4. If I am going in the right direction, I can complete the problem. Im just not sure this is how to set it up.
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Algebra.Com's Answer #212654 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
1/x+1/x+1=9/4
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\n" ); document.write( "Let x & (x+2) be the 2 consecutive EVEN integers.
\n" ); document.write( "The reciprocal of the second integer is 1/(x+2)
\n" ); document.write( "x+1/(x+2)=9/4
\n" ); document.write( "Find the common denominator for the left side terms.
\n" ); document.write( "[x(x+2)+1]/(x+2)=9/4
\n" ); document.write( "[x^2+2x+1)/(x+2)=9/4
\n" ); document.write( "Cross multiply.
\n" ); document.write( "4(x^2+2x+1)=9(x+2)
\n" ); document.write( "4x^2+8x+4=9x+18
\n" ); document.write( "4x^2+8x-9x+4-18=0
\n" ); document.write( "4x^2-x-14=0
\n" ); document.write( "(4x+7)(x-2)=0
\n" ); document.write( "x-2=0
\n" ); document.write( "x=2 ans. for the first even integer.
\n" ); document.write( "2+2=4 ans. for the second even integer.
\n" ); document.write( "Proof:
\n" ); document.write( "2+1/(2+2)=9/4
\n" ); document.write( "2+1/4=9/4
\n" ); document.write( "8/4+1/4=9/4
\n" ); document.write( "9/4=9/4
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