document.write( "Question 294959: How would you solve the equation .25^x-0.5=2 ? \n" ); document.write( "
Algebra.Com's Answer #212629 by helpnalgebra(91)\"\" \"About 
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25^(x)-0.5=2
\n" ); document.write( "25^(x)=0.5+2
\n" ); document.write( "25^(x)=2.5
\n" ); document.write( "ln(25^(x))=ln(2.5)
\n" ); document.write( "xln(25)=ln(2.5)
\n" ); document.write( "xln(25)=(0.92)
\n" ); document.write( "(xln(25))/(ln(25))=(0.92)/(ln(25))\r
\n" ); document.write( "\n" ); document.write( "x=(0.92)/(ln(25))_xAPPR0.28 answer
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