document.write( "Question 294871: X, Y and Z can do a job in 10 days. X leaves after working with Y and Z for 4 days, and then Y and Z completes the remaining work in 10 more days. In how many days, X alone can do the work. \n" ); document.write( "
Algebra.Com's Answer #212581 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 10/x+10/y+10/z=1 \n" ); document.write( "4/10+10/y+10/z=1 \n" ); document.write( "10/x=2/5 \n" ); document.write( "2x=50 \n" ); document.write( "x=25 \n" ); document.write( "x can do the job in 25 days \n" ); document.write( " \n" ); document.write( " |