document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294741>Question 294741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joshua is doing a chemistry experiment that calls for a 30% solution of copper sulfate. He has 40 mL of 25% solution. How many milliliters of 60% solution should Joshua add to obtain the required 30% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212532 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joshua is doing a chemistry experiment that calls for a 30% solution of copper sulfate. He has 40 mL of 25% solution. How many milliliters of 60% solution should Joshua add to obtain the required 30% solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.25*40 + 0.60x = 0.30(40+x)<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "1000 + 60x = 30*40 + 30x<BR>\n" );
document.write( "30x = 200<BR>\n" );
document.write( "x = 6 2/3 mL (amt. of 60% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );