document.write( "Question 35037: How many ounces each of a 12% alcohol solution and a 30% alcohol solution must be combined to obtain 60 ounces of an 18% solution? \n" ); document.write( "
Algebra.Com's Answer #21253 by Prithwis(166)![]() ![]() ![]() You can put this solution on YOUR website! Let the answer be x \n" ); document.write( "Then .12x + .30(60-x)= .18(60) \n" ); document.write( "=> 12x + 30(60-x) = 18(60) \n" ); document.write( "=> -18x = -720 \n" ); document.write( "=> x=40 \n" ); document.write( "... \n" ); document.write( "40 ounces of 12% alcohol is needed to mix with 20 ounces of 30% alocohol to prepare 60 ounces of 18% alocohol. \n" ); document.write( " \n" ); document.write( " |