document.write( "Question 35037: How many ounces each of a 12% alcohol solution and a 30% alcohol solution must be combined to obtain 60 ounces of an 18% solution? \n" ); document.write( "
Algebra.Com's Answer #21253 by Prithwis(166)\"\" \"About 
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Let the answer be x
\n" ); document.write( "Then .12x + .30(60-x)= .18(60)
\n" ); document.write( "=> 12x + 30(60-x) = 18(60)
\n" ); document.write( "=> -18x = -720
\n" ); document.write( "=> x=40
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\n" ); document.write( "40 ounces of 12% alcohol is needed to mix with 20 ounces of 30% alocohol to prepare 60 ounces of 18% alocohol.
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