document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294619>Question 294619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of the current in a river is 2 mph.  Jay travels 20 miles upstream and 2o miles downstream in 5 1/3 hours.  What is the speed of the boat? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212512 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "20=(R+2)T<BR>\n" );
document.write( "T=20/(R+2) FOR THE TRIP DOWNSTREAM.<BR>\n" );
document.write( "D=RT<BR>\n" );
document.write( "20=(R-2)T<BR>\n" );
document.write( "T=20/(R-2) FOR THE TRIP UPSTREAM.<BR>\n" );
document.write( "ADD THE TWO TIMES.<BR>\n" );
document.write( "20/(R+2)+20/(R-2)=5 1/3<BR>\n" );
document.write( "[20(R+2)+20(R-2)]/(R+2)(R-2)=16/3<BR>\n" );
document.write( "[20R+40+20R-40]/(R^2-4)=16/3 CROSS MULTIPLY.<BR>\n" );
document.write( "16(R^2-4)=3(40R)<BR>\n" );
document.write( "16R^2-64=120R<BR>\n" );
document.write( "16R^2-12OR-64=0<BR>\n" );
document.write( "8(2R^2-15R-8)=0<BR>\n" );
document.write( "8(2R+1)(R-8)=0<BR>\n" );
document.write( "R-8=0<BR>\n" );
document.write( "R=8 MPH IS THE BOAT SPEED IN STILL WATER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "20/(8+2)+20/(8-2)=16/3<BR>\n" );
document.write( "20/10+20/6=16/3<BR>\n" );
document.write( "2+10/316/3<BR>\n" );
document.write( "6/3+10/3=16/3<BR>\n" );
document.write( "16/3=16/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );