document.write( "Question 294694: The numbers which divide 80 in such a way that the sum of their reciprocals is
\n" ); document.write( "4/75 are :\r
\n" ); document.write( "\n" ); document.write( "(a) 40, 40 (b) 35, 45 (c) 30, 50 (d) 60, 20\r
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Algebra.Com's Answer #212474 by richwmiller(17219)\"\" \"About 
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1/x+1/y=4/75
\n" ); document.write( "x+y=80
\n" ); document.write( "x=30 and y=50
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\n" ); document.write( "1/30+1/50=4/75
\n" ); document.write( "multiply by 150
\n" ); document.write( "5+3=8
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