document.write( "Question 35037: How many ounces each of a 12% alcohol solution and a 30% alcohol solution must be combined to obtain 60 ounces of an 18% solution? \n" ); document.write( "
Algebra.Com's Answer #21246 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the solution be x \n" ); document.write( "12x+30(60-x)=18(60) \n" ); document.write( "-18x=-720 \n" ); document.write( "x=40 \n" ); document.write( "60-40=20 \n" ); document.write( "Hence, for 12% about 40 ounces is needed and for 30% about 20 ounces is needed. \n" ); document.write( "PAul. \n" ); document.write( " |