document.write( "Question 35037: How many ounces each of a 12% alcohol solution and a 30% alcohol solution must be combined to obtain 60 ounces of an 18% solution? \n" ); document.write( "
Algebra.Com's Answer #21246 by Paul(988)\"\" \"About 
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Let the solution be x
\n" ); document.write( "12x+30(60-x)=18(60)
\n" ); document.write( "-18x=-720
\n" ); document.write( "x=40
\n" ); document.write( "60-40=20
\n" ); document.write( "Hence, for 12% about 40 ounces is needed and for 30% about 20 ounces is needed.
\n" ); document.write( "PAul.
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