document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294688>Question 294688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how can i find out the length of the slant height of a cone with a radius of 15 cm ad a surface area of 1884 cm square? thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212459 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The surface area of right circular cone = pi*r^2 +pi*r*l\r<BR>\n" );
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document.write( "The radius =15 cm\r<BR>\n" );
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document.write( "area = 1884 sq. cm\r<BR>\n" );
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document.write( "1884= pi*(15)^2 + pi*15*l\r<BR>\n" );
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document.write( "1884= 15pi(15+l)\r<BR>\n" );
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document.write( "1884 /15*pi =15+l\r<BR>\n" );
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document.write( "1884/15*pi -15= l\r<BR>\n" );
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document.write( "l  = 25 cms\r<BR>\n" );
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