document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294690>Question 294690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd numbers such that four times the first number decreased by 28 is the same as the sum of the last two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212455 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the three consequitive numbers be x,  x+2 , x+4\r<BR>\n" );
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document.write( "4times the first number decreased by 28\r<BR>\n" );
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document.write( "=4x-28\r<BR>\n" );
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document.write( "this is equal to sum of second two numbers\r<BR>\n" );
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document.write( "x+2 and x+4\r<BR>\n" );
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document.write( "4x-28=x+4 +x+2\r<BR>\n" );
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document.write( "4x-28=2x+6\r<BR>\n" );
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document.write( "4x-2x= 28+6\r<BR>\n" );
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document.write( "2x=34\r<BR>\n" );
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document.write( "x=17\r<BR>\n" );
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document.write( "So the numbers are 17,19,21\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );