document.write( "Question 294638: Please help me solve this equation. The question is find two consecutive odd integers such that the sum of their reciprocals is 12/35. \n" ); document.write( "
Algebra.Com's Answer #212438 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! (1 / n) + [1 / (n + 2)] = 12 / 35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "35n + 70 + 35n = 12n^2 + 24n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = 12n^2 - 46n - 70\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = 6n^2 - 23n - 35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = (6n + 7) (n - 5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 5 ___ n + 2 = 7 \n" ); document.write( " |