document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294650>Question 294650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is six times its width.<BR>\n" );
document.write( "If the area of the rectangle is 216 in ^2, find its perimeter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212437 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width be x\r<BR>\n" );
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document.write( "the length will be 6x\r<BR>\n" );
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document.write( "the area = L*W \r<BR>\n" );
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document.write( "6x*x+216\r<BR>\n" );
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document.write( "6x^2=216\r<BR>\n" );
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document.write( "x^2=216/6\r<BR>\n" );
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document.write( "x^2=36\r<BR>\n" );
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document.write( "x=6 which is the width\r<BR>\n" );
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document.write( "the length will be 6*6=36\r<BR>\n" );
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document.write( "the perimeter will be 2L+2W\r<BR>\n" );
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document.write( "2*6 + 2*36\r<BR>\n" );
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document.write( "12+72\r<BR>\n" );
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document.write( "=84 --- perimeter<BR>\n" );
document.write( " </SPAN>\n" );
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