document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294636>Question 294636</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If a and b be two vectors and m be a scalar, then how can I show that <BR>\n" );
document.write( " m(a+b)=ma+mb </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212423 by </B><A HREF=/tutors/aboutme.mpl?userid=helpnalgebra><B>helpnalgebra(91)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=helpnalgebra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=helpnalgebra><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok i tried this 3 ways to get answer for m a and b\r<BR>\n" );
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document.write( "m(a+b)=ma+mb<BR>\n" );
document.write( "ma+mb=m(a+b)<BR>\n" );
document.write( "am+bm=am+bm<BR>\n" );
document.write( "am+bm-am-bm=0<BR>\n" );
document.write( "0+bm-bm=0\r<BR>\n" );
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document.write( "0=0  answer\r<BR>\n" );
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document.write( "m(a+b)=ma+mb<BR>\n" );
document.write( "am+bm=am+bm<BR>\n" );
document.write( "am+bm-am=bm<BR>\n" );
document.write( "0+bm=bm<BR>\n" );
document.write( "bm=bm<BR>\n" );
document.write( "(bm)/(m)=(bm)/(m)<BR>\n" );
document.write( "b=(bm)/(m)\r<BR>\n" );
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document.write( "b=b answer\r<BR>\n" );
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document.write( "m(a+b)=ma+mb<BR>\n" );
document.write( "am+bm=am+bm<BR>\n" );
document.write( "am+bm-bm=am<BR>\n" );
document.write( "am=am<BR>\n" );
document.write( "(am)/(m)=(am)/(m)<BR>\n" );
document.write( "a=(am)/(m)\r<BR>\n" );
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document.write( "a=a answer\r<BR>\n" );
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document.write( "this was tricky for me.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );