document.write( "Question 294493: I have a piece of cardboard that is twice as long as it is wide. If I cut a 2-inch by 2-inch square from each corner and fold up the resulting flaps, I get a box with a volume of 6720 cubic inches. What are the dimensions of the cardboard? \n" ); document.write( "
Algebra.Com's Answer #212332 by checkley77(12844)\"\" \"About 
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W=2L
\n" ); document.write( "(W-4)(L-4)*2=6,720
\n" ); document.write( "(2L-4)(L-4)*2=6,720
\n" ); document.write( "(2L^2-4L-8L+16)*2=6,720
\n" ); document.write( "4L^2-24L+32-6,720=0
\n" ); document.write( "4L^2-24L-6,688=0
\n" ); document.write( "4(L^2-6L-1,672)=0
\n" ); document.write( "4(L-44)(L+38)=0
\n" ); document.write( "L-44=0
\n" ); document.write( "L=44 INCHES FOR THE LENGTH OF THE CARDBOARD.
\n" ); document.write( "W=2*44=88 INCHES IS THE WIDTH OF THE CARDBOARD.
\n" ); document.write( "PROOF:
\n" ); document.write( "(88-4)(44-4)*2=6,720
\n" ); document.write( "84*40*2=6,720
\n" ); document.write( "6,720=6,720
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