document.write( "Question 294493: I have a piece of cardboard that is twice as long as it is wide. If I cut a 2-inch by 2-inch square from each corner and fold up the resulting flaps, I get a box with a volume of 6720 cubic inches. What are the dimensions of the cardboard? \n" ); document.write( "
Algebra.Com's Answer #212332 by checkley77(12844) ![]() You can put this solution on YOUR website! W=2L \n" ); document.write( "(W-4)(L-4)*2=6,720 \n" ); document.write( "(2L-4)(L-4)*2=6,720 \n" ); document.write( "(2L^2-4L-8L+16)*2=6,720 \n" ); document.write( "4L^2-24L+32-6,720=0 \n" ); document.write( "4L^2-24L-6,688=0 \n" ); document.write( "4(L^2-6L-1,672)=0 \n" ); document.write( "4(L-44)(L+38)=0 \n" ); document.write( "L-44=0 \n" ); document.write( "L=44 INCHES FOR THE LENGTH OF THE CARDBOARD. \n" ); document.write( "W=2*44=88 INCHES IS THE WIDTH OF THE CARDBOARD. \n" ); document.write( "PROOF: \n" ); document.write( "(88-4)(44-4)*2=6,720 \n" ); document.write( "84*40*2=6,720 \n" ); document.write( "6,720=6,720 \n" ); document.write( " \n" ); document.write( " |