document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294449>Question 294449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 1 ft less than 3 times the width. the area of the rectangle is 310 ft. what are the dimensions of the rectangle.   When i did the question i got w = 77.75 but when substituted in the equations that didn't make sense the equations i used were L*W=310 and 3W-1=L </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212303 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l=-1+3w<BR>\n" );
document.write( "l=3w-1<BR>\n" );
document.write( "l*w=310<BR>\n" );
document.write( "(3w-1)*w=310<BR>\n" );
document.write( "3w^2-w-310=0<BR>\n" );
document.write( "w= 31/3<BR>\n" );
document.write( "w= 10 1/3<BR>\n" );
document.write( "l=31/3*3-1<BR>\n" );
document.write( "l=30<BR>\n" );
document.write( "30*31/3=10*31=310\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );