document.write( "Question 294351: Use the formula: s=n^2+n
\n" ); document.write( " all over 2
\n" ); document.write( "1. where S is the sum of the first n natural numbers. How
\n" ); document.write( "many consecutive natural numbers beginning with 1 will give a sum of 120 ?\r
\n" ); document.write( "\n" ); document.write( "2.where S is the sum of the first n natural numbers. How
\n" ); document.write( "many consecutive natural numbers beginning with 1 will give a sum of 253?
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Algebra.Com's Answer #212268 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Use the formula: s=n^2+n
\n" ); document.write( "all over 2
\n" ); document.write( "1. where S is the sum of the first n natural numbers. How
\n" ); document.write( "many consecutive natural numbers beginning with 1 will give a sum of 120 ?
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\n" ); document.write( "120 = (n^2+n)/2
\n" ); document.write( "n^2+n = 240
\n" ); document.write( "n^2+n-240 = 0
\n" ); document.write( "(n-15)(x+16) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "n = 15 (# of natural numbers, 1,2,...n whose sum is 120
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\n" ); document.write( "2.where S is the sum of the first n natural numbers. How
\n" ); document.write( "many consecutive natural numbers beginning with 1 will give a sum of 253?
\n" ); document.write( "Use the same procedure as above.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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