document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294260>Question 294260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For a wedding, Shereda bought several dozen roses and several dozen carnations. The roses cost $15 per dozen, and the carnations cost $8 per dozen. Shereda bought a total of 17 dozen flowers and paid a total of $192. How many roses did she buy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212238 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So we have two equations:   r = roses   c= carnations<BR>\n" );
document.write( "1) r + c = 17<BR>\n" );
document.write( "2) 15r + 8c = 192\r<BR>\n" );
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document.write( "Use substitution:  so take equation 1 subtract r from both sides and make it<BR>\n" );
document.write( "c = 17 - r   Now sub it into equation 2\r<BR>\n" );
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document.write( "15r + 8(17-r) = 192<BR>\n" );
document.write( "15r + 136 - 8r = 192<BR>\n" );
document.write( "7r + 136 = 192  subtract 136 from both sides<BR>\n" );
document.write( "7r = 56 divide by 7<BR>\n" );
document.write( "r = 8  now use r = 8 in equation 1\r<BR>\n" );
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document.write( "8 + c = 17<BR>\n" );
document.write( "c = 9\r<BR>\n" );
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document.write( "so you will have 8 dozen roses and 9 dozen carnations </SPAN>\n" );
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