document.write( "Question 294210: logx + log(x-3)=1 \n" ); document.write( "
Algebra.Com's Answer #212213 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! 1. Write as one log isolated on one side.\r \n" ); document.write( "\n" ); document.write( "log[x(x - 3)] = 1\r \n" ); document.write( "\n" ); document.write( "2. Write in exponential form.\r \n" ); document.write( "\n" ); document.write( "Base = 10, exponent = 1\r \n" ); document.write( "\n" ); document.write( "10^1 = x(x - 3)\r \n" ); document.write( "\n" ); document.write( "3. Solve for x.\r \n" ); document.write( "\n" ); document.write( "10 = x^2 - 3x\r \n" ); document.write( "\n" ); document.write( "0 = x^2 - 3x - 10\r \n" ); document.write( "\n" ); document.write( "0 = (x - 5)(x + 2)\r \n" ); document.write( "\n" ); document.write( "Can you finish now?\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |