document.write( "Question 294082: Question 1: Sarah takes 6 hours to complete a job which mary could do in half the time. how many hours would it take to complete the job if they both worked together?\r
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document.write( "Question 2: The time it takes to empty a tank varies inversely as the rate of pumping. if a pump working at 600 kl/min takes 45 minutes to empty a tank. how long would it take to empty the same tank if the rate was increased to 1000 kl/min?\r
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document.write( "Any help will be greatly appreciated. thx you very much in advance. \n" );
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Algebra.Com's Answer #212200 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Question 1: Sarah takes 6 hours to complete a job which mary could do in half the time. \n" ); document.write( " how many hours would it take to complete the job if they both worked together? \n" ); document.write( ": \n" ); document.write( "From the given information we know Mary takes 3 hrs to complete the job \n" ); document.write( ": \n" ); document.write( "Let t = time required when they work together \n" ); document.write( ": \n" ); document.write( "Let the competed job = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply by 6, results: \n" ); document.write( "t + 2t = 6 \n" ); document.write( "3t = 6 \n" ); document.write( "t = 2 hrs working together \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Question 2: The time it takes to empty a tank varies inversely as the rate of pumping. \n" ); document.write( " if a pump working at 600 kl/min takes 45 minutes to empty a tank. \n" ); document.write( " how long would it take to empty the same tank if the rate was increased to 1000 kl/min? \n" ); document.write( ": \n" ); document.write( "Let x = time required when pumping 1000kl/min \n" ); document.write( ": \n" ); document.write( "An inverse ratio equation \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "1000x = 600 * 45 \n" ); document.write( "x = \n" ); document.write( "x = 27 min when it pumps at 1000kl/min \n" ); document.write( " |