document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=294162>Question 294162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sides of a right triangle are x,x+32,and x+32 units long. What is the length of the hypotenuse? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212190 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since 'x' is positive, this means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3Cx%2B32 ALIGN=MIDDLE  ALT=\"x%3Cx%2B32\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Also, because we have two sides of length x+2, this means that the legs are x+2 units long leaving the hypotenuse to be 'x' units long. That's where the problem lies: the hypotenuse cannot be shorter than either leg. So either there's a typo, or something is missing. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );