document.write( "Question 34979This question is from textbook Algebra and Trigonometry Structure and Method
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document.write( ": A boat traveled 36 km downstream in 2h. the return trip upstream took 3 h. find the rate of the current. \r
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document.write( "i got d=rt
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document.write( "downstream 72=(x+y)5
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document.write( "upstream 72=(x-y)5
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document.write( "then i solved for x and got 180 but when i tried for y everything cancels itself out, help please... \n" );
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Algebra.Com's Answer #21217 by Paul(988) ![]() You can put this solution on YOUR website! Let the speed of the boat be x \n" ); document.write( "Let the speed of the current be y \n" ); document.write( "Equation 1: \n" ); document.write( "2x+2y=36 \n" ); document.write( "y=18-x (subsitution) \n" ); document.write( "3x-3y=36 \n" ); document.write( "Subsitute for yL \n" ); document.write( "3x-3(18-x)=36 \n" ); document.write( "6x=36+54 \n" ); document.write( "x=15 \n" ); document.write( "y=18-15 \n" ); document.write( "y=3 \n" ); document.write( "Hence, the speed of the boat is 15mph And the speed of the current is 3mph. \n" ); document.write( "Paul. \n" ); document.write( " |