document.write( "Question 34979This question is from textbook Algebra and Trigonometry Structure and Method
\n" ); document.write( ": A boat traveled 36 km downstream in 2h. the return trip upstream took 3 h. find the rate of the current. \r
\n" ); document.write( "\n" ); document.write( "i got d=rt
\n" ); document.write( "downstream 72=(x+y)5
\n" ); document.write( "upstream 72=(x-y)5
\n" ); document.write( "then i solved for x and got 180 but when i tried for y everything cancels itself out, help please...
\n" ); document.write( "

Algebra.Com's Answer #21217 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
Let the speed of the boat be x
\n" ); document.write( "Let the speed of the current be y
\n" ); document.write( "Equation 1:
\n" ); document.write( "2x+2y=36
\n" ); document.write( "y=18-x (subsitution)
\n" ); document.write( "3x-3y=36
\n" ); document.write( "Subsitute for yL
\n" ); document.write( "3x-3(18-x)=36
\n" ); document.write( "6x=36+54
\n" ); document.write( "x=15
\n" ); document.write( "y=18-15
\n" ); document.write( "y=3
\n" ); document.write( "Hence, the speed of the boat is 15mph And the speed of the current is 3mph.
\n" ); document.write( "Paul.
\n" ); document.write( "
\n" );