document.write( "Question 293932: a right triangle is 16cm longer than the shortest side and 2cm longer than the remaining side. Find the dimensions of the triangle \n" ); document.write( "

Algebra.Com's Answer #212130 by checkley77(12844) $\"\"$ $\"About$

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THe lengths of the 3 sides are:
\n" ); document.write( "x, 16+x & 2+x
\n" ); document.write( "x^2+(2+x)^2=(16+x)^2
\n" ); document.write( "x^2+4+4x+x^2=256+32x+x^2
\n" ); document.write( "2x^2-x^2+4x-32x+4-256=0
\n" ); document.write( "x^2-28x-252=0
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "x=(28+-sqrt[-28^2-4*1*-252])/2*1
\n" ); document.write( "x=(28+-sqrt[784+1,008])/2
\n" ); document.write( "x=(28+-sqrt1,792)/2
\n" ); document.write( "x=(28+-42.332)/2
\n" ); document.write( "x=(28+42.332)/2
\n" ); document.write( "x=70.332/2
\n" ); document.write( "x=35.166 ans.
\n" ); document.write( "x=(28-42.332)/2
\n" ); document.write( "x=-14.332/2
\n" ); document.write( "x=-7.166 ans. \n" ); document.write( "

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