document.write( "Question 293944: The perimeter of a rectangle is 18 feet, and the area of the rectangle is 20 square feet. What is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #212120 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 18=2L+2W \n" ); document.write( "20=LW OR L=20/W \n" ); document.write( "18=2*20/W+2W \n" ); document.write( "18=40/W+2W \n" ); document.write( "18=(40+2W*W)/W \n" ); document.write( "18=(40+2W^2)/W \n" ); document.write( "40+2W^2=W*18 \n" ); document.write( "40+2W^2=18W \n" ); document.write( "2W^2-18W+40=0 \n" ); document.write( "2(W^2-9W+20)=0 \n" ); document.write( "2(W-5)(W-4)=0 \n" ); document.write( "W-5=0 \n" ); document.write( "W=5 ANS. L=20/5=4 ANS. \n" ); document.write( "W-4=0 \n" ); document.write( "W=4 ANS. L=20/4=5 ANS. \n" ); document.write( "PROOFS: \n" ); document.write( "20=4*5 \n" ); document.write( "20=20 \n" ); document.write( "18=2*4+2*5 \n" ); document.write( "18=8+10 \n" ); document.write( "18=18 \n" ); document.write( " |