document.write( "Question 293944: The perimeter of a rectangle is 18 feet, and the area of the rectangle is 20 square feet. What is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #212120 by checkley77(12844)\"\" \"About 
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18=2L+2W
\n" ); document.write( "20=LW OR L=20/W
\n" ); document.write( "18=2*20/W+2W
\n" ); document.write( "18=40/W+2W
\n" ); document.write( "18=(40+2W*W)/W
\n" ); document.write( "18=(40+2W^2)/W
\n" ); document.write( "40+2W^2=W*18
\n" ); document.write( "40+2W^2=18W
\n" ); document.write( "2W^2-18W+40=0
\n" ); document.write( "2(W^2-9W+20)=0
\n" ); document.write( "2(W-5)(W-4)=0
\n" ); document.write( "W-5=0
\n" ); document.write( "W=5 ANS. L=20/5=4 ANS.
\n" ); document.write( "W-4=0
\n" ); document.write( "W=4 ANS. L=20/4=5 ANS.
\n" ); document.write( "PROOFS:
\n" ); document.write( "20=4*5
\n" ); document.write( "20=20
\n" ); document.write( "18=2*4+2*5
\n" ); document.write( "18=8+10
\n" ); document.write( "18=18
\n" ); document.write( "
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