document.write( "Question 293954: Solve for x. Log2x – Log4x+ Log8x = 5 \n" ); document.write( "
Algebra.Com's Answer #212090 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve for x. Log2x – Log4x+ Log8x = 5 \n" ); document.write( "---- \n" ); document.write( "Assuming that the 2,4, and 8 are base numbers you get: \n" ); document.write( "Log2(x) - (1/2)Log2(x) + (1/3)log2(x) = 5 \n" ); document.write( "----- \n" ); document.write( "log2(x) - log2(x^(1/2)) + log2(x^(1/3)) = 5 \n" ); document.write( "--- \n" ); document.write( "log2[(x*x^(1/3))/x^(1/2)] = 5 \n" ); document.write( "--- \n" ); document.write( "log2[x^(4/3-1/2)] = 5 \n" ); document.write( "--- \n" ); document.write( "x^(5/8) = 5 \n" ); document.write( "--- \n" ); document.write( "x = 5^(8/5) \n" ); document.write( "x = 13.13.. \n" ); document.write( "================= \n" ); document.write( "Assuming the 2x, 4x, and 8x are all inverse logs you get: \n" ); document.write( "log(2x) - log(4x) + log(8x) = 5 \n" ); document.write( "--- \n" ); document.write( "log[(2x)(8x)/(4x)] = 5 \n" ); document.write( "--- \n" ); document.write( "log(4x) = 5 \n" ); document.write( "--- \n" ); document.write( "4x = 10^5 \n" ); document.write( "x = (1/4)(100,000) \n" ); document.write( "x = 250,000 \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |