document.write( "Question 293807: Two Joggers, one averaging 9 mph and one averaging 5 mph, start from a designated initial point. The slower jogger arrives at the end of the run 15 minutes after the other jogger. Find the distance of the run. \n" ); document.write( "
Algebra.Com's Answer #212086 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Two Joggers,
\n" ); document.write( "one averaging 9 mph and one averaging 5 mph, start from a designated initial point.
\n" ); document.write( "The slower jogger arrives at the end of the run 15 minutes after the other jogger.
\n" ); document.write( " Find the distance of the run.
\n" ); document.write( ":
\n" ); document.write( "let t = the time of the faster jogger
\n" ); document.write( "then
\n" ); document.write( "(t+.25) = time of the slower jogger
\n" ); document.write( ":
\n" ); document.write( "We know they both travel the same distance
\n" ); document.write( ":
\n" ); document.write( "Change 15 min to .25 hr
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation
\n" ); document.write( ":
\n" ); document.write( "9t = 5(t+.25)
\n" ); document.write( ":
\n" ); document.write( "9t = 5t + 1.25
\n" ); document.write( ":
\n" ); document.write( "9t - 5t = 1.25
\n" ); document.write( ":
\n" ); document.write( "4t = 1.25
\n" ); document.write( "t = \"1.25%2F4\"
\n" ); document.write( "t = .3125 hrs
\n" ); document.write( ":
\n" ); document.write( "Find the distance
\n" ); document.write( ".3125 * 9 = 2.8125 miles
\n" ); document.write( "check the distance
\n" ); document.write( "(.3125+.25) * 5 = 2.8125 miles \n" ); document.write( "
\n" );