document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=293819>Question 293819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two numbers is 84. The first number is divided by 3 and the second number is multiplied by 4. The product of the two new numbers is then divided by 2. What is the final result of this calculation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212041 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> xy=84<BR>\n" );
document.write( "((x/3)*4y)/2=<BR>\n" );
document.write( "x/3*2y=<BR>\n" );
document.write( "2xy/3=<BR>\n" );
document.write( "2*84/3=<BR>\n" );
document.write( "168/3=56\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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