document.write( "Question 293812: Average age of students of an adult school is 40 years. 120 new students whose average age is 32 years joined the school. As a result the average age is decreased by 4 years. Find the number of students of the school after joining of the new students:\r
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document.write( "(a) 1200 (b) 120 (c) 360 (d) 240 \n" );
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Algebra.Com's Answer #212000 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the number of students be x. The sum of all their ages = 40x\r \n" ); document.write( "\n" ); document.write( "120 joined \r \n" ); document.write( "\n" ); document.write( "total is x+120\r \n" ); document.write( "\n" ); document.write( "The sum of all their ages = 40x+ 120*32\r \n" ); document.write( "\n" ); document.write( "=40x + 3840\r \n" ); document.write( "\n" ); document.write( "average age now is 36\r \n" ); document.write( "\n" ); document.write( "40x+3840 / x+120 =36\r \n" ); document.write( "\n" ); document.write( "40x+3820 = 36(x+120)\r \n" ); document.write( "\n" ); document.write( "40x+3840 =36x + 4320\r \n" ); document.write( "\n" ); document.write( "40x-36x= 4320-3840\r \n" ); document.write( "\n" ); document.write( "4x= 480\r \n" ); document.write( "\n" ); document.write( "x= 120\r \n" ); document.write( "\n" ); document.write( "initially there were 120. 120 joined. so total isd 240 students \n" ); document.write( " |