document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=293755>Question 293755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by any method:\r<BR>\n" );
document.write( "\n" );
document.write( "5x + 6y =14<BR>\n" );
document.write( "-3y+  x =7  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211978 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x + 6y = 14   and<BR>\n" );
document.write( "-3y + x = 7\r<BR>\n" );
document.write( "\n" );
document.write( "I think substitution would be the easiest\r<BR>\n" );
document.write( "\n" );
document.write( "so let's rearrange -3y + x = 7 so add 3y to both sides\r<BR>\n" );
document.write( "\n" );
document.write( "x = 3y + 7  now substitute into the first equation and solve\r<BR>\n" );
document.write( "\n" );
document.write( "5(3y + 7) + 6y = 14<BR>\n" );
document.write( "15y + 35 + 6y = 14<BR>\n" );
document.write( "21y + 35 = 14  subtract 35 from both sides<BR>\n" );
document.write( "21y = -21  divide by 21<BR>\n" );
document.write( "y = -1\r<BR>\n" );
document.write( "\n" );
document.write( "Now we know y = -1  use the first equation again and use -1 for y<BR>\n" );
document.write( " 5x + 6(-1) = 14<BR>\n" );
document.write( "5x - 6 = 14  add 6 to both sides<BR>\n" );
document.write( "5x = 20  divide by 5<BR>\n" );
document.write( "x = 4\r<BR>\n" );
document.write( "\n" );
document.write( "so now you have your cordinate  (4, -1) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );