document.write( "Question 293726: FIND A, if $7000 is invested at 8% compounded continously for 2 years.\r
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\n" ); document.write( "\n" ); document.write( "if $400 is invested at 3% compunded continously, how many years(to the nearest tenth) would it take for the investment to double?
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Algebra.Com's Answer #211976 by alex224(8)\"\" \"About 
You can put this solution on YOUR website!
First you need to know the continuous compounding formula and it is A=Pe^rt\r
\n" ); document.write( "\n" ); document.write( "A=ammount
\n" ); document.write( "p=principle
\n" ); document.write( "e=continuous button on calculator
\n" ); document.write( "r=rate
\n" ); document.write( "t=time\r
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\n" ); document.write( "\n" ); document.write( "then plug in what you know\r
\n" ); document.write( "\n" ); document.write( "A=7000e^(.08)(2)\r
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\n" ); document.write( "\n" ); document.write( "then plug into a calculator and make sure to use enough parenthesis\r
\n" ); document.write( "\n" ); document.write( "A=(7000e^(.08)(2))\r
\n" ); document.write( "\n" ); document.write( "the final answer should be\r
\n" ); document.write( "\n" ); document.write( "$15166.02\r
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\n" ); document.write( "\n" ); document.write( "the next part of the problem is asking for time so you put in what you got for A and use the new information\r
\n" ); document.write( "\n" ); document.write( "15166.02=400e^(.03)(t)\r
\n" ); document.write( "\n" ); document.write( "first devide both sides by 400\r
\n" ); document.write( "\n" ); document.write( "37.91505=e^.03t\r
\n" ); document.write( "\n" ); document.write( "37.91505=1.03045t\r
\n" ); document.write( "\n" ); document.write( "t=36.8 years\r
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