document.write( "Question 293451: Mr. Brown purchased $1,775 worth of stock, some at $3.25 per share and some at $4.50 per share. If he bought a total of 500 shares of stock, how many shares of each did he buy? \n" ); document.write( "

Algebra.Com's Answer #211963 by ddkumara(1) $\"\"$ $\"About$

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Let x be the no of share per $3.25
\n" ); document.write( "Let y be no of share per $4.50\r
\n" ); document.write( "\n" ); document.write( "x + y = 500 --------- (1)
\n" ); document.write( "3.25x + 4.50y = 1775 --------- (2)\r
\n" ); document.write( "\n" ); document.write( "Multiply equation (1) by 4.50 we get\r
\n" ); document.write( "\n" ); document.write( "4.50x + 4.50y = 2250 --------- (3)
\n" ); document.write( "3.25x + 4.50y = 1775\r
\n" ); document.write( "\n" ); document.write( "Subtract (3) - (2)\r
\n" ); document.write( "\n" ); document.write( "1.25x = 475
\n" ); document.write( " x = 475/1.25
\n" ); document.write( " x = 380\r
\n" ); document.write( "\n" ); document.write( "x = 380 plugging in (1) we get\r
\n" ); document.write( "\n" ); document.write( "x + y = 500
\n" ); document.write( "380 + y = 500
\n" ); document.write( " y = 500 - 380
\n" ); document.write( " y = 120\r
\n" ); document.write( "\n" ); document.write( "Number of shares he purchased 380 and 120. \n" ); document.write( "

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