document.write( "Question 293618: I am trying to find the vertex for : f(x)=-x^2+10x+5. I am stuck...
\n" ); document.write( "(-x^2+10x+25-25)+5
\n" ); document.write( "(-x^2+10x+25)+(25+5)
\n" ); document.write( "(x+5)(x+5)
\n" ); document.write( "I think I am doing this wrong. The negative in front of the x^2 is throwing me off... any help will be appreciated!
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Algebra.Com's Answer #211908 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Standard \"vertex form\" is
\n" ); document.write( "y= a(x-h)^2+k
\n" ); document.write( "where (h,k) is the vertex
\n" ); document.write( ".
\n" ); document.write( "-x^2+10x+5
\n" ); document.write( "First group the x terms:
\n" ); document.write( "-(x^2-10x)+5
\n" ); document.write( "Complete square:
\n" ); document.write( "-(x^2-10x+__)+5
\n" ); document.write( "-(x^2-10x+25)+5+25
\n" ); document.write( "-(x-5)^2+30
\n" ); document.write( "So, the vertex is at:
\n" ); document.write( "(5,30)\r
\n" ); document.write( "\n" ); document.write( "
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