document.write( "Question 293618: I am trying to find the vertex for : f(x)=-x^2+10x+5. I am stuck...
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document.write( "(-x^2+10x+25-25)+5
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document.write( "(-x^2+10x+25)+(25+5)
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document.write( "(x+5)(x+5)
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document.write( "I think I am doing this wrong. The negative in front of the x^2 is throwing me off... any help will be appreciated! \n" );
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Algebra.Com's Answer #211908 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Standard \"vertex form\" is \n" ); document.write( "y= a(x-h)^2+k \n" ); document.write( "where (h,k) is the vertex \n" ); document.write( ". \n" ); document.write( "-x^2+10x+5 \n" ); document.write( "First group the x terms: \n" ); document.write( "-(x^2-10x)+5 \n" ); document.write( "Complete square: \n" ); document.write( "-(x^2-10x+__)+5 \n" ); document.write( "-(x^2-10x+25)+5+25 \n" ); document.write( "-(x-5)^2+30 \n" ); document.write( "So, the vertex is at: \n" ); document.write( "(5,30)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |