document.write( "Question 34935: Anothe one that is confusing to me. Thank you for your help! THIS IS A HARD ONE!\r
\n" ); document.write( "\n" ); document.write( "Solve any way and show work.
\n" ); document.write( "How many 3-digit numbers are possible using 2,3,5, or 7 if you DO NOT repeat digits?
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Algebra.Com's Answer #21190 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
OK long way first:\r
\n" ); document.write( "\n" ); document.write( "235 325 523 723
\n" ); document.write( "237 327 527 725
\n" ); document.write( "253 352 532 732
\n" ); document.write( "257 357 537 735
\n" ); document.write( "273 372 572 752
\n" ); document.write( "275 375 573 753\r
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\n" ); document.write( "\n" ); document.write( "there are no other 3 digit numbers made up from 2,3,5 or 7.\r
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\n" ); document.write( "\n" ); document.write( "So... \"quick\" method:
\n" ); document.write( "Think of the number like ABC... how many numbers could be placed in position A? Answer any of the 4.
\n" ); document.write( "OK, so we have a number in position A. Whatever it is, we now have 3 numbers left to put into position B, so altogether we have 4*3 possibilities.
\n" ); document.write( "And finally we have 2 numbers to put into position C, so altogether we have 4*3*2 permutations --> 24.\r
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\n" ); document.write( "\n" ); document.write( "Count the number of examples i wrote at the start: there are 24 different 3 digit numbers.\r
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\n" ); document.write( "\n" ); document.write( "jon
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