document.write( "Question 293490: how do you find the distance between the pair of points (5,-5) and (1,-2)? \n" ); document.write( "
Algebra.Com's Answer #211870 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=5\" and \"y%5B1%5D=-5\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=1\" and \"y%5B2%5D=-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%285-1%29%5E2%2B%28-5--2%29%5E2%29\" Plug in \"x%5B1%5D=5\", \"x%5B2%5D=1\", \"y%5B1%5D=-5\", and \"y%5B2%5D=-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%284%29%5E2%2B%28-5--2%29%5E2%29\" Subtract \"1\" from \"5\" to get \"4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%284%29%5E2%2B%28-3%29%5E2%29\" Subtract \"-2\" from \"-5\" to get \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2816%2B%28-3%29%5E2%29\" Square \"4\" to get \"16\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2816%2B9%29\" Square \"-3\" to get \"9\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2825%29\" Add \"16\" to \"9\" to get \"25\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=5\" Take the square root of \"25\" to get \"5\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=5\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is 5 units.
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