document.write( "Question 293477: The perimeter of a rectangle is 34 feet. Find the width of the rectangle if the length is 5 feet more than twice the width.
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Algebra.Com's Answer #211859 by Deina(147)\"\" \"About 
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\n" ); document.write( "2L + 2W = 34
\n" ); document.write( "l = 2w + 5\r
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\n" ); document.write( "\n" ); document.write( "2(2w + 5) + 2w = 34\r
\n" ); document.write( "\n" ); document.write( "4w + 10 + 2w = 34 Combine like terms:
\n" ); document.write( "6w + 10 = 34

\n" ); document.write( "Subtract 10 from each side:
\n" ); document.write( "6w = 24

\n" ); document.write( "Divide both sides by 6
\n" ); document.write( "w = 4 Width equals 4

\n" ); document.write( "Substitute 4 for w calculate length:
\n" ); document.write( "l = 2(4) +5
\n" ); document.write( "l = 13 Length = 13

\n" ); document.write( "replace l with 13 and w with 4 to check your answer:
\n" ); document.write( "2(13) + 2(4) = 34 and bob's your uncle!
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