document.write( "Question 293090: The area of a certain rectangle is 36. If the ratio of the rectangle to the width of the rectangle is 4 to 1, what is the perimeter of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #211769 by ankor@dixie-net.com(22740)\"\" \"About 
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O added the word \"length\" to make this make sense\r
\n" ); document.write( "\n" ); document.write( "The area of a certain rectangle is 36.
\n" ); document.write( " If the ratio of the rectangle LENGTH to the width of the rectangle is 4 to 1, what is the perimeter of the rectangle?
\n" ); document.write( ":
\n" ); document.write( "Let x = the width
\n" ); document.write( "then
\n" ); document.write( "4x = the length
\n" ); document.write( ":
\n" ); document.write( "Find x using the area
\n" ); document.write( "4x * x = 36
\n" ); document.write( "4x^2 = 36
\n" ); document.write( "x^2 = \"36%2F4\"
\n" ); document.write( "x^2 = 9
\n" ); document.write( " x = 3
\n" ); document.write( "then
\n" ); document.write( "4(3) = 12; the length
\n" ); document.write( ";
\n" ); document.write( "The perimeter
\n" ); document.write( "2(12) + 2(3) = 30 \n" ); document.write( "
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