document.write( "Question 34948: A bicyclist took a ride to the country and it took 5 hours. To get back she went 5mph faster and it took 4 hours. What were the speeds, going and coming? \n" ); document.write( "
Algebra.Com's Answer #21174 by AnlytcPhil(1810) You can put this solution on YOUR website! \r\n" ); document.write( "A bicyclist took a ride to the country and it took 5 hours.\r\n" ); document.write( "To get back she went 5mph faster and it took 4 hours. What \r\n" ); document.write( "were the speeds, going and coming?\r\n" ); document.write( "\r\n" ); document.write( "Make this chart\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time \r\n" ); document.write( "Going | | | | \r\n" ); document.write( "Coming | | | |\r\n" ); document.write( "\r\n" ); document.write( "Let x = the speed going in mph\r\n" ); document.write( "\r\n" ); document.write( ">>...To get back she went 5mph faster...<<\r\n" ); document.write( "\r\n" ); document.write( "So the speed coming back = x+5 mph. So fill in these \r\n" ); document.write( "speeds\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time \r\n" ); document.write( "Going | | x | | \r\n" ); document.write( "Coming | | x+5 | | \r\n" ); document.write( "\r\n" ); document.write( ">>...A bicyclist took a ride to the country and it took \r\n" ); document.write( "5 hours...<<\r\n" ); document.write( "\r\n" ); document.write( ">>...To get back...it took 4 hours...<<\r\n" ); document.write( "\r\n" ); document.write( "So fill in 5 hours and 4 hours for the times:\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time \r\n" ); document.write( "Going | | x | 5 | \r\n" ); document.write( "Coming | | x+5 | 4 | \r\n" ); document.write( "\r\n" ); document.write( "Now use Distance = Rate × Time to fill in the distances\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time \r\n" ); document.write( "Going | 5x | x | 5 | \r\n" ); document.write( "Coming | 4(x+5) | x+5 | 4 | \r\n" ); document.write( "\r\n" ); document.write( "Now since the distance going equals the distance back, we\r\n" ); document.write( "form an equation by setting the two distances equal\r\n" ); document.write( "\r\n" ); document.write( " 5x = 4(x+5)\r\n" ); document.write( "\r\n" ); document.write( "Solve that and get x = 20 mph going, then since the speed\r\n" ); document.write( "returning is 5mph more, the returning speed is 25 mph.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r\n" ); document.write( "AnlytcPhil@aol.com\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |