document.write( "Question 293272: I need to solve for X over interval {0, 2pi)
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document.write( "4cos2x=sqrt3\r
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document.write( "I tried dividing out 4 but then am stuck with cos2x(which is an identity) = sqrt3/4.\r
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document.write( "Then im left with 2cos^2x - 1 = sqrt3/4.\r
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document.write( "Should I turn the cos2x into its identity before dividing out 4?\r
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document.write( "If anyone can help me get on track that would be great! \n" );
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Algebra.Com's Answer #211730 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I need to solve for X over interval {0, 2pi) \n" ); document.write( "4cos2x=sqrt3 \n" ); document.write( "--- \n" ); document.write( "cos(2x) = (1/4)sqrt(3) \n" ); document.write( "--- \n" ); document.write( "Take the arcos of each side to get: \n" ); document.write( "2x = arcos[(sqrt(3)/4] \n" ); document.write( "--- \n" ); document.write( "2x = 64.34 degrees \n" ); document.write( "x = 32.17 degrees \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |