document.write( "Question 293272: I need to solve for X over interval {0, 2pi)
\n" ); document.write( "4cos2x=sqrt3\r
\n" ); document.write( "\n" ); document.write( "I tried dividing out 4 but then am stuck with cos2x(which is an identity) = sqrt3/4.\r
\n" ); document.write( "\n" ); document.write( "Then im left with 2cos^2x - 1 = sqrt3/4.\r
\n" ); document.write( "\n" ); document.write( "Should I turn the cos2x into its identity before dividing out 4?\r
\n" ); document.write( "\n" ); document.write( "If anyone can help me get on track that would be great!
\n" ); document.write( "

Algebra.Com's Answer #211730 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I need to solve for X over interval {0, 2pi)
\n" ); document.write( "4cos2x=sqrt3
\n" ); document.write( "---
\n" ); document.write( "cos(2x) = (1/4)sqrt(3)
\n" ); document.write( "---
\n" ); document.write( "Take the arcos of each side to get:
\n" ); document.write( "2x = arcos[(sqrt(3)/4]
\n" ); document.write( "---
\n" ); document.write( "2x = 64.34 degrees
\n" ); document.write( "x = 32.17 degrees
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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