document.write( "Question 293273: I am stuck on this problem where I need to solve for X.\r
\n" ); document.write( "\n" ); document.write( "(tan^-1) 2x= -pi/6 \r
\n" ); document.write( "\n" ); document.write( "If anyone could help it would be much appreciated!
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Algebra.Com's Answer #211724 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
... Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " ... Take the tangent of both sides to eliminate the inverse tangent.\r
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\n" ); document.write( "\n" ); document.write( " ... Break up the tangent into sine over cosine \r
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\n" ); document.write( "\n" ); document.write( " ... Evaluate the sine of \"-pi%2F6\" to get \"-1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( " ... Evaluate the cosine of \"-pi%2F6\" to get \"sqrt%283%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( " ... Multiply the first fraction by the reciprocal of the second fraction.\r
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\n" ); document.write( "\n" ); document.write( " ... Multiply and simplify\r
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\n" ); document.write( "\n" ); document.write( " ... Rationalize the denominator of the fraction on the right side.\r
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\n" ); document.write( "\n" ); document.write( " ... Divide both sides by 2. \r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=-sqrt%283%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "Edit: Take note that \"-sqrt%283%29%2F6=-1%2F%282%2Asqrt%283%29%29\" (just do a bit of algebraic manipulation)
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