document.write( "Question 293254: the perimeter of a rectangle is 56m, the length is 10m more than twice the width, find the dimension
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Algebra.Com's Answer #211714 by checkley77(12844)\"\" \"About 
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L=2W+10
\n" ); document.write( "P=2L+2W
\n" ); document.write( "56=2(2W+10)+2W
\n" ); document.write( "56=4W+20+2W
\n" ); document.write( "56=6W+20
\n" ); document.write( "6W=56-20
\n" ); document.write( "6W=36
\n" ); document.write( "W=36/6
\n" ); document.write( "W=6 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*6+10
\n" ); document.write( "L=12+10=22 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "56=2*22+2*6
\n" ); document.write( "56=44+12
\n" ); document.write( "56=56
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