document.write( "Question 293254: the perimeter of a rectangle is 56m, the length is 10m more than twice the width, find the dimension
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Algebra.Com's Answer #211714 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+10 \n" ); document.write( "P=2L+2W \n" ); document.write( "56=2(2W+10)+2W \n" ); document.write( "56=4W+20+2W \n" ); document.write( "56=6W+20 \n" ); document.write( "6W=56-20 \n" ); document.write( "6W=36 \n" ); document.write( "W=36/6 \n" ); document.write( "W=6 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*6+10 \n" ); document.write( "L=12+10=22 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "56=2*22+2*6 \n" ); document.write( "56=44+12 \n" ); document.write( "56=56 \n" ); document.write( " |