document.write( "Question 293257: Write the equation(S) in function form, please. 5x-y=-1 and 2y+3x=2 \r
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Algebra.Com's Answer #211703 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "First we must solve for y:\r
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\n" ); document.write( "\n" ); document.write( "\"5x-y=-1\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-y=-1-5x\" Subtract \"5x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-y=-5x-1\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-5x-1%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-5%29%2F%28-1%29%29x%2B%28-1%29%2F%28-1%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=5x%2B1\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now replace 'y' with f(x) to get \"f%28x%29=5x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "So the function is \"f%28x%29=5x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "Again, we must solve for y:\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2B3x=2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2y=2-3x\" Subtract \"3x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2y=-3x%2B2\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-3x%2B2%29%2F%282%29\" Divide both sides by \"2\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-3%29%2F%282%29%29x%2B%282%29%2F%282%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-%283%2F2%29x%2B1\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now replace 'y' with f(x) to get \"f%28x%29=-%283%2F2%29x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "So the function is \"f%28x%29=-%283%2F2%29x%2B1\"
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