document.write( "Question 293255: solve by completing the square 3/8x^2 = 1/8 - x
\n" ); document.write( "Get 0 on one side: 3/8x^2 + x - 1/8 = 0
\n" ); document.write( "Divide both sides by 8 and then you get: 3x^2+8x-1 =0
\n" ); document.write( "Then I make the coefficient of x^2 equal to 1, I divide both sides by 3, term by term.
\n" ); document.write( "Then I get x^2 + 8/3 - 1/3 = 0
\n" ); document.write( "This is where I get confused. I need help completing the square now. I know I square 1/2(8/3)^2 and that gives me a square and I add 16/9 to both sides. \r
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Algebra.Com's Answer #211699 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve by compleing the square:
\n" ); document.write( "\"%283%2F8%29x%5E2+=+%281%2F8%29-x\" Get into standard form.
\n" ); document.write( "\"%283%2F8%29x%5E2%2Bx-1%2F8+=+0\" Multiply both sides by \"%288%2F3%29\"
\n" ); document.write( "\"x%5E2%2B%288%2F3%29x-1%2F3+=+0\" Add \"1%2F3\" to both sides.
\n" ); document.write( "\"x%5E2%2B%288%2F3%29x+=+1%2F3\" Now complete the square by adding the square of half the coefficient of the x-term. \"%28%281%2F2%29%288%2F3%29%29%5E2+=+16%2F9\" to both sides.
\n" ); document.write( "\"x%5E2%2B%288%2F3%29x%2B16%2F9+=+%281%2F3%29%2B%2816%2F9%29\" Simplify.
\n" ); document.write( "\"%28x%2B%284%2F3%29%29%5E2+=+19%2F9\" Take the square root of both sides.
\n" ); document.write( "\"x%2B%284%2F3%29+=+sqrt%2819%29%2F3\" or \"x%2B%284%2F3%29+=+-sqrt%2819%29%2F3\" Subtract \"4%2F3\" from both sides.
\n" ); document.write( "\"x+=+-%284%2F3%29+%2B+sqrt%2819%29%2F3\" or \"-%284%2F3%29-sqrt%2819%29%2F3\"
\n" ); document.write( "\"x+=+%28-4-sqrt%2819%29%29%2F3\" or \"%28-4-sqrt%2819%29%29%2F3\" \n" ); document.write( "
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