document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=293240>Question 293240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am working on a Radical equation not sure how to start other than plug in the numbers for what I am trying to find the right way to start this problem P=1500radicalt+P0 with t= the year and P0 = population of the town, trying to find out different population scenarios. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211687 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=1500radicalt+P0 with t= the year and P0 = population of the town<BR>\n" );
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document.write( "Population = 1500*sqrt(t) + P(0)<BR>\n" );
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document.write( "The graph would be a line with slope = 1500<BR>\n" );
document.write( "and y-intercept of P(0).<BR>\n" );
document.write( "chart from the year 2010 till 2016; would that mean dividing 1500 into the year sqrt(t) for each year?<BR>\n" );
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document.write( "If P(0) is the population count in 2010,<BR>\n" );
document.write( "P(2010) = 1500*sqrt(0) + P(0)<BR>\n" );
document.write( "P(2016) = 1500*sqrt(6) + P(0)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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