document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=293141>Question 293141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction on parallel tracks. Train A is traveling 60 miles per hour and Train B at 80 mile per hour. Train A passes a station at 8:20am, if train B passes the same station at 8:35am, at what time will train B catch up to train A?<BR>\n" );
document.write( "When will train B catch up with train A?______ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211616 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 60 mph 8:20<BR>\n" );
document.write( "b 80 mph 8:35<BR>\n" );
document.write( "a has a head start of 15 minutes which is 1/4 hr.<BR>\n" );
document.write( "in 1/4 hr it goes 15 miles<BR>\n" );
document.write( "train b is catching up at 20 miles and hr. so it will catch up in 45 minutes<BR>\n" );
document.write( "8:35 +0:45=8:80=9:20 am <BR>\n" );
document.write( "We can also write it:<BR>\n" );
document.write( "60*(x+1/4)=80x<BR>\n" );
document.write( "60x+15=80x<BR>\n" );
document.write( "15=20x<BR>\n" );
document.write( "15/20=3/4=x<BR>\n" );
document.write( "3/4 hr=45 minutes same as above<BR>\n" );
document.write( "Train B catches train A at 9:20 am. ANSWER </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );