document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=293176>Question 293176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The numerator of a certain fraction is 3 less than the denominator. If the numerator is tripled and the denominator is increased by 7, the resulting fraction is equal to 3/2. What was the original fraction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211607 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3*(x-3)/(x+7)=3/2<BR>\n" );
document.write( "x=13<BR>\n" );
document.write( "30/20<BR>\n" );
document.write( "o=(x-3)/x<BR>\n" );
document.write( "o=10/13 <BR>\n" );
document.write( "original fraction =10/13<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );