document.write( "Question 293123: I was working on this math problem and I can't seem to figure it out. I was wondering if someone could help me? Please and Thank You! I would deeply appreicate it!\r
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document.write( "Circles:Circles and Lengths of Segments
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document.write( "A bridge over a river has the shape of a circular arc. The span of the bridge is 24 meters. (The span is the length of the chord of the arc.) The midpoint of the arc is 4 meters higher than the endpoints. What is the radius of the circle that contains this arc? \n" );
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Algebra.Com's Answer #211586 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A bridge over a river has the shape of a circular arc. \n" ); document.write( " The span of the bridge is 24 meters. (The span is the length of the chord of the arc.) \n" ); document.write( " The midpoint of the arc is 4 meters higher than the endpoints. What is the radius of the circle that contains this arc? \n" ); document.write( ": \n" ); document.write( "Solve a right triangle formed by the radius (r), half the chord, and dist from center to the chord \n" ); document.write( ": \n" ); document.write( "r = the hypotenuse \n" ); document.write( "(r-4) = one leg, (dist from center to chord) \n" ); document.write( "12 = one leg (half the length of the chord) \n" ); document.write( ": \n" ); document.write( "r^2 = 12^2 + (r-4)^2 \n" ); document.write( "r^2 = 144 + r^2 - 8r + 16 \n" ); document.write( "Subtract r^2 from both sides \n" ); document.write( "0 = -8r + 160 \n" ); document.write( "8r = 160 \n" ); document.write( "r = \n" ); document.write( "r = 20 m is the radius of the circle containing this arc \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check by solving the right triangle: \n" ); document.write( "distance from center to chord: 20 - 4 = 16 \n" ); document.write( "r = \n" ); document.write( "r = 20 \n" ); document.write( " |