document.write( "Question 292970: The supplement of an angle measures 40\" more than twice its complement. Find the measure of the angle. \n" ); document.write( "
Algebra.Com's Answer #211571 by ankor@dixie-net.com(22740)\"\" \"About 
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Assume you mean 40 degrees, not 40 seconds
\n" ); document.write( "The supplement of an angle measures 40 degrees more than twice its complement.
\n" ); document.write( " Find the measure of the angle.
\n" ); document.write( ":
\n" ); document.write( "Let x = the angle
\n" ); document.write( "then
\n" ); document.write( "(90-x) = it's complement
\n" ); document.write( "and
\n" ); document.write( "(180-x) = it's supplement
\n" ); document.write( ":
\n" ); document.write( "Write an equation for the statement:
\n" ); document.write( "\"The supplement of an angle measures 40 degrees more than twice its complement.\"
\n" ); document.write( "180 - x = 2(90-x) + 40
\n" ); document.write( ":
\n" ); document.write( "180 - x = 180 - 2x + 40
\n" ); document.write( ":
\n" ); document.write( "-x + 2x = 180 - 180 + 40
\n" ); document.write( ":
\n" ); document.write( "x = 40 degrees
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the statement
\n" ); document.write( " The supplement of an angle measures 40 degrees more than twice its complement.
\n" ); document.write( "180 - 40 = 2(90-40) + 40
\n" ); document.write( "140 = 2(50) + 40 \n" ); document.write( "
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